http://www.cab.zju.edu.cn/chinese/2024/0509/c11148a2527045/page.htm WebAug 27, 2024 · Scaffold N50 :Scaffold N50与Contig N50的定义类似.Contigs拼接组装获得一些不同长度的Scaffolds.将所有的Scaffold长度相加,能获得一个Scaffold总长度.然后将所有的Scaffolds按照从长到短进行排序,如获得Scaffold 1,Scaffold 2,Scaffold 3...………Scaffold 25.将Scaffold按照这个顺序依次相加,当相加的长度达到Scaffold总长度的一半时,最后一 …
Contig N50和Scaffold N50 - 简书
WebApr 17, 2024 · 测 序策略: PacBio RS II +Sanger 测序. 组装结果:基因组大小为 61.1 Mb , Contig N50 : 78.2Kb ; Scaffold N50 : 1.3 Mb , GC 含量为 38.5% , Scaffold 水平。. 组学策略: F. cylindrus 在不同环境相关的生长条件进行培育(连续光照、黑暗、低铁、冰冻、升温和 CO2 ),进行 RNA-Seq 测序。 圆柱拟脆杆藻( F. cylindrus ... In computational biology, N50 and L50 are statistics of a set of contig or scaffold lengths. The N50 is similar to a mean or median of lengths, but has greater weight given to the longer contigs. It is used widely in genome assembly, especially in reference to contig lengths within a draft assembly. There are … See more N50 N50 statistic defines assembly quality in terms of contiguity. Given a set of contigs, the N50 is defined as the sequence length of the shortest contig at 50% of the total assembly length. It … See more N50 can be found mathematically for a list L of positive integers as follows: 1. Create another list L' , which is identical to L, except that every element n in L has been replaced with n … See more Consider two fictional, highly simplified genome assemblies, A and B, that are derived from two different species. Assembly A contains six contigs of lengths 80 kbp, 70 kbp, 50 kbp, 40 kbp, 30 kbp, and 20 kbp. The sum size of assembly A is 290 … See more • Herfindahl–Hirschman Index See more • contig_info: A tool to estimate standard descriptive statistics from contig sequences, e.g. N(G)50, N(G)75, N(G)90, L(G)50, L(G)75, L(G)90, auN ... See more the cashman wins
高通量测序各参数计算方法(二) - 知乎 - 知乎专栏
WebN50 ,L50和NG50是评价genome assembly的quality的标准,评价长度时使用N50,N50是一个contig的长度。 不选用genome size的50% 是因为1.这是估计的size值不一定准;2.sequence 仅覆盖80%。 评价数量使用L50,L50数量越小越好。 NG50表达测到genome 覆盖度。 取材方法很重要,得到目标数据。 Assembly 算法有可能带来更多误差,通常二 … WebJan 22, 2024 · 而且我们得到几乎与PacBio一样的scafflod N50值。 当然,仅仅使用ONT,是无法达到这种水平的scaffold N50值的。 而且(使用stLFR+少量ONT的)基因组的碎片数远低于仅使用ONT的。 好。这是一些实际示例,说明了我们如何将其应用于从头测序项目。 WebMay 8, 2024 · 对于一个组装出来的序列,不论是contig还是scaffold, 首先将各个序列根据长度从大到小排序,然后从第一个序列开始,将长度进行累加,直到累加的长度超过了总长 … taunton school international term dates